To get the complete list of possible values, please refer to the Redshift Documentation. The DIFFERENCE function compares the American Soundex codes of two strings. timestampdiff (a text,b timestamp, c timestamp ) RETURNS INT AS $$ BEGIN case when a=second then datediff (second,b,c) when a=minute then. datepart. Expected behavior On using the datediff function on redshift, it should give a normal result. For example the result must be something like 45:15:10 Both data warehouse platforms offer online support, but Snowflake also provides 24/7 live support. SELECT (EXTRACT(epoch from age('2017-6-15', now())) / 86400)::int In Redshift, you can use date_trunc() (See online documentation). This can be up to 128 TB per node, reaching potentially petabytes of data in a cluster. It appears that Redshift supports two possible functions for computing a time interval distance between two DATE -like objects: DATEDIFF () & date_diff (). The usage of the datediff is similar in all the databases except for the parameters that we. In PostgreSQL, you can take the difference in years, multiply by 12 and add. At the time of insertion date into the timestamp datatype column, the value of date will be implicitly converted into the fully timestamp value. select to_date ( '20010631', 'YYYYMMDD', FALSE ); The result is July 1, 2001, because there are only 30 days. This function is especially useful for calculating intervals, such as the number of days between two dates or the hours between two timestamps. To calculate the difference between two timestamps, you can use the DATEDIFF () command: DATEDIFF () accepts the same values as EXTRACT () and DATE_PART (). 0. The argument order is in the order of the interval notation: [start_date, end_date] SELECT DATEDIFF( MONTH DATE '2020-02-03', DATE. Sorted by: 0. PostgreSQL - Date Difference in Months. 例えば、 12-31-2008 と 01-01-2009 の 2 つの日付間で年の差を計算しているとします。. The data that is used by the job depends on the data type of a particular column. Redshift will place the query in a paused state temporarily. Currently I am only returning 1. 0. 2. The date part to which to truncate the timestamp value. The time zone for the return value. 8XL clusters with equivalently sized Medium, Large and X-Large Snowflake configurations: Redshift is 1. Trunc function works on both date and numeric types. 3x less expensive than Snowflake for on-demand pricing; Redshift is 1. Snowflake vs Redshift - learn 10 differences between these DW. . The difference between 2017-11-04 00:00:00 and 2017-11-22 10:21:00. It appears that Redshift supports two possible functions for computing a time interval distance between two DATE -like objects: DATEDIFF () & date_diff (). Results can include various columns and metadata. The following example adds 30 minutes to a date value that doesn't specify a timestamp. DATEPART ( date_part ,. date_to) - (DATEDIFF(WK, evnt. 0. this continues till the end of the week. However, some of the functions were not working using Amazon Redshift. 543081. It calculates the difference in years between the birth date and the date in one year (minus one day) to account for partial years. Push out all due dates by one week. 00274 because of the leap year. Redshift Spectrum reduces the time and effort required to perform analysis. timeworkedfrom >= date_trunc ('month', current_date) - interval '6. AWS's Redshift provides the extract function: EXTRACT ( datepart FROM { TIMESTAMP 'literal' | timestamp } ) The datepart takes various values including epoch - you can therefore extract the epoch from a timestamp e. For example, SELECT DATEDIFF (day, '2036-03-01', '2036-02-28'); returns -2, hinting that 2036 must be a leap year. Returns the difference between two dates or times for a given date part, such as a day. Amazon Redshift supports the comparison operators described in the following table: Value a is less than value b. Hey guys, I am created a derived table in Looker and I understand it runs on redshift, as such, I trying to get something similar to below as an aggregated table: I have two tables: Customers and Orders I want to get Cust. The second column gives the day of week (numerically, between 0 and 6). The parameterized snippet below can be used to find the number of weekdays between 2 dates. Number of weekdays between two dates - StartDate question. id, count(*) cnt_past60_days from mytable t join dates d on t. We named this one. event_id, evnt. Part of AWS Collective. Sign up for free to join this conversation on GitHub . Returns the <date> with the specified number <interval> added to the specified <date_part> of that date. SUPER type. Is there a way around this, or a way to predetermine which date is null up front? (psudocode)The solution: detect and release locks to avoid stuck queries in Amazon Redshift. For example, suppose that you're calculating the difference in years between two dates, 12-31-2008 and 01-01-2009. In Redshift, you can use datediff () and arithmetics: select t. Then, the last_value function will take last value per row and the distinct removes all irrelevant rows from the output. To view a list of. This will draw the distinct pairs of id's and dates out and rejoin them onto the dataset only where the joined dates are earlier than the row in question. timeworkedfrom >= DATEADD (MONTH, -6, DATEADD (month, DATEDIFF (month, 0, GETDATE ()), 0)) to this: AND be. The following format strings apply to functions such as TO_CHAR. Check the Amazon Redshift Advisor recommendations. In physics, a redshift is an increase in the wavelength, and corresponding decrease in the frequency and photon energy, of electromagnetic radiation (such as light). The range condition includes the begin and end values. AWS Redshift was one of the first cloud data warehouses to become available on the market, officially launching in 2013. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. The 15 date functions with examples are the most commonly used ones by Redshift developers. However, since the requirement is to generate monthly reports which I would assume to be a. For instance, one contrasting comparison is that Amazon Redshift Serverless doesn't have the concept of a cluster or node. time = b. (DATEDIFF(sec,starttime,endtime)) avg_duration, MIN(starttime) as oldest_ts,. The following example finds the difference in number. Takes three arguments, the start date, the end date. The default column name for the DATEDIFF function is DATE_DIFF. AWS Redshift clusters require some manual maintenance. NAME, table2. This function is especially useful for calculating intervals, such as the number of days between two. For example, because the common calendar starts from the year 1, the first decade (decade 1) is 0001-01-01 through 0009-12-31, and the second decade (decade 2) is 0010-01-01 through 0019-12-31. This question is in a. sql. Use an interval literal to identify specific periods of time, such as 12 hours or 6 weeks. datepart. WITH DateCte AS ( SELECT idcode, mydatetime, RANK () OVER ( ORDER BY idcode) AS CurrentRank, (RANK () OVER ( ORDER BY idcode) + 1 )AS NextRank FROM Table1 ) SELECT ce. select datediff (qtr, '1998-07-01', current_date); date_diff ----------- 40 (1 row) En este ejemplo, se unen las tablas SALES y LISTING para calcular cuántos días después de indicarse se vendieron los tickets de los listados 1000 a 1005. SQL Date Diff Business Days. When the table grows larger, Amazon Redshift might change the distribution. create user user 1 password 'md 5153 c 434 b 4 b 77 c 89 e 6 b 94 f 12 c 5393 af 5 b'; Log on to the database using the sign-in credentials. A data type constrains the set of values that a column or argument can contain. 2 Answers. The following SQL statement converts the date 02 Oct 2001 into a date data type. 0. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. Test Result (I tested it in Oracle 18c. The first example in that case is not correct it should start with 6/1/2018 not 5/1/2018. この場合、これらの日付は 1 日しか離れていないにもかかわらず、関数は 1 年を返します。. If the result is positive, the Secure Agent returns negative values and if the result is negative, the positive value is returned. The default column name for a DATEADD function is DATE_ADD. most_recent) However, I am running into issues where the timestamp is the same. The opposite change, a decrease in wavelength and simultaneous increase in frequency and energy, is known as a blueshift, or negative redshift. This would be equivalent. We use the following syntax: if <condition> <code_block1> else <code_block2> endif. Not the 1st one as it perform unnecessary (unless you really have such unprocessed data) truncate. You can extract part of a timestamp by applying the EXTRACT. date1)) AS difference FROM t t1 INNER JOIN t t2 ON t1. 1. . select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. The Redshift DATEDIFF function is used to calculate the difference between two date values based on the interval specified using either Years, Months, Days, Weeks, Hours, Minutes, Seconds, Milliseconds, et al. The following format strings apply to functions such as TO_CHAR. set timezone to ‘xxx36’; ISO-8601 Offset – The offset from UTC in the form ± [hh]: [mm]. MONTHS_BETWEEN function. not just the whole number of years). The preferred method for this is to copy the existing table. Follow. datepart. The target column or expression that the function operates on. Unfortunately this. BigQuery also supports a separate DATE_DIFF function that will return the difference between two date types, unlike the DATETIME_DIFF that only supports the datetime type. Amazon Redshift doesn't validate POSIX-style time zone specifications, so it is possible to set the time zone to an invalid value. date1 > t2. Rather, it returns the difference between the dates specified by datepart. AWS Collective See more. DATEDIFF is providing rows where the month itself was 3 months or less. 0 / 60 / 24 as diff from mytable t. 2. Here expr2 is lesser than expr1, so the return value is negative. But on the last day of the week (day Friday), the total number will reflect. Returns the <date> with the specified number <interval> added to the specified <date_part> of that date. Use this function to calculate the number of business days excluding Saturday and Sunday. person_id. Redshift DATEDIFF Function. If you are not sure about this then use the CDate function to ensure that the value in the cells is converted to a date before passing to the DateDiff function e. Date functions to manipulate date data types in Redshift. It's fairly trivial do something like. For example, if you are calculating the difference in years between two dates, 12-31-2008 and 01-01-2009, the function returns 1 year despite the fact that these dates are only one day apart. SELECT table1. This function returns the truncated timestamp or interval with a particular level of precision. If you just add time parameter up to, how many digits your need after seconds like below. 2. agency. A Soundex code represents how a word sounds rather than how it is spelled. The DATE_PART function allows you to extract a specified date part from a date/time. createddate, table2. 2. Transforming date with Redshift. . date1 GROUP by t1. Implementing DATEDIFF in Redshift simply computes the difference between two dates or timestamps. To calculate the difference between two dates in the same column, we use the createdDate column of the registration table and apply the DATEDIFF function on that column. Step 2: Add the Amazon Redshift cluster public key to the host's authorized keys file; Step 3: Configure the host to accept all of the Amazon Redshift cluster's IP addresses; Step 4: Get the public key for the host; Step 5: Create a manifest file; Step 6: Upload the manifest file to an Amazon S3 bucket; Step 7: Run the COPY command to load the dataConsidering Sunday as the first day of the week the below statements in redshift should return 2 as the week number instead returning 1. Getting the differences between two specified time values where the time is specified in the format of YYYY-MM-DD HH-MM-SS. In most use cases, Snowflake correctly handles date and timestamp values formatted as strings. g. DATE_DIFF function Examples. 2. BigQuery also supports a separate DATE_DIFF function that will return the difference between two date types, unlike the DATETIME_DIFF that only supports the datetime type. The default timestamp with time zone (TIMESTAMPTZ) format is YYYY-MM-DD HH:MI:SSOF, where OF is the offset from UTC (for example, -8:00. You can name date parts in full or abbreviate them. Share. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. In Redshift, you can use date_trunc() (See online documentation). A date field or a call to another function that outputs a date. Amazon Redshift interprets the DECADE or DECADES DATEPART based on the common calendar. For the rest I use new_start and new_end - 1 second. Redshift is designed and optimized to store and access much larger data sets than RDS. <code_block1> – The code block. Note. A DATE, TIME, TIMETZ, or TIMESTAMP column or an expression that implicitly converts to a DATE, TIME, TIMETZ, or TIMESTAMP. Follow answered Sep 13, 2017 at 1:40. Redshift provides the different types of built-in functions to perform the different operations on the data as per user requirements. To define an external table in Amazon Redshift, use the CREATE EXTERNAL TABLE command. GETDATE ()関数 / CURRENT_DATE - 現在時刻 これは、現在の日時を取得するのに使います。. I want to calculate the months_in_inventory by calculating the difference between a fixed_date and the inventory_date. Sorted by: 1. The following example returns the date of the last day in the current month. state = b. Many companies are using Amazon Redshift to analyze and transform their data. Amazon Redshift allows users to query data, either by connecting with their desired cluster and then executing queries using the AWS Query Editor or by using an external SQL-based client such as MySQL Workbench. date1, t2. Amazon Redshift computes the resulting scale dynamically based on the scales of the operands. This is actually quite a complex problem because it involves: Hours within a day. select datediff (day, saletime, last_day (saletime)) as. The Verdict. You can use these interval literals in conditions and calculations that involve datetime expressions. Create timestampdiif function in Redshift. AWS Collective See more. The following code snippet provides an example of this behavior: SELECT datediff (DAYS, '2021-01-01'::DATE, '2021-02-01'::DATE) AS datediff_interval_output , datediff ('day', '2021-01-01. Likewise is there any function in redshift that I could use to get the correct week number. In the example the fixed_date is '2020-12-20' and I am using it my query. Firstly, let's look at which data types for time series are supported by Redshift and what kind of data they can hold. Now I am trying to make this query dynamic such that it can give me count for past 6 weeks something like below as an output: Count Week ------------ 124 W43 125 W42 126 W41 127 W40 128 W39 129 W38. date_from, evnt. など. select to_date ('02 Oct 2001', 'DD Mon YYYY'); to_date ------------ 2001-10-02 (1 row) The following SQL statement converts the string 20010631 to a date. For example, decade 201 spans from 2000-01-01 to 2009-12-31: 2. The default timestamp for a date value is 00:00:00. CDT. The following example returns the number of tickets sold for each of the last 7 days of the month. 0'. I'm trying to Implement Netezza AGE function in Redshift as a UDF. 2, I used the below query to get the date before 12 months. Datediff with join returning not expected result. 338+ Hours of HD Videos 54 Courses 4 Mock Tests & Quizzes Verifiable Certificate of Completion Lifetime Access 4. Syntax TO_DATE ( string, format) TO_DATE ( string, format, is_strict) Arguments string A string to be converted. Add a policy that denies permission to redshift:GetClusterCredentials. Use the TIMESTAMPTZ data type to input complete timestamp values that include the date, the time of day, and a time zone. DATEDIFF. DATEDIFF ( datepart, expression1, expression2) datepartには、年、月、日、時、分、秒などの特定の粒度を指定し、expression1, expression2には日付の列、または、 timestamp の式を指定する。. dbeaver. I would like to calculate number of days between two dates in redshift but the function should take into account the time that's mean day=0 if there is less than 24 hours between the dates like Timestampdiff function in MySQL. Here is the code used in RS. Athena charges per-query, based on the bytes of data scanned and rounded up to the nearest MB, at a rate of $5 per terabyte (though this can vary by region). The Redshift Datepart function returns the interval value as an integer. Example 5: Use Current Date. To be clear, I need any year fraction as well (ie. If either argument is null, the result is NULL. Amazon Redshift data sharing allows you to securely share live, transactionally consistent data in one Amazon Redshift cluster with another Amazon Redshift cluster across accounts and Regions, without. 3. In certain cases, such as string-based comparisons or when a result depends on a different timestamp format than is set in the session parameters, we recommend explicitly converting. Thank you. This is the documentation for the Amazon Redshift Developer Guide - amazon-redshift-developer-guide/r_DATEDIFF_function. month, week or hour, and it will return the truncated timestamp or interval with the level of precision. You can directly convert the format by specifying the cast operator ( ‘::’) such as ::date, ::time, ::timestamp after the date string literal. Select now ()::time; It outputs something like: 09:23:49. Basically, there are two ways to create the indexes in Redshift as follows. Let’s look at the clear differences between the two. I need to find the difference between start_date_time and end_date_time, such that, if difference is 1 day, then result should be 1. There are lots of Python libraries. Public Holiday. select on_call, on_call::int * interval '1 second' from dev_isaac. 1. So, your query should be: select email, createddate, lastloggedin, datediff (minute, createddate, lastloggedin) from udb. The snippet can then be called in a query as shown below: select [difference_in_weekdays ('2017-06-20','2018-07-16')] Which returns 279. 7x less expensive than Snowflake with the purchase of a 1 or 3 year Reserved. *First need to sort both files: proc sort data=data_333; by client id; proc sort data=test_data; by client id; *then need to merge and get differences; Data Test; MERGE data_333 (in=a) test_data (in=b);Converting Valid Character Strings to Dates, Times, or Timestamps. Name and group by those, and also get the minimum Order. HLLSKETCH type. date is in datetime. Improve this answer. Example 5: Use Current Date. AWS Redshift vs Snowflake: A quick comparison. Amazon Redshift allocates the workload to the cluster nodes and. This can be replace by a recursive CTE (or keep a "dates" table on your database). mydatetime, ne. SELECT * FROM tickets t LEFT JOIN d_customer c ON c. Instead: select (case when 1=1 then datediff (month, '2009-01-01', '2009-12-31') else datediff (month, '2009-01-01', '2009-12-31') end) as nummonths; I assume this is oversimplified code, because obviously the case is not needed in any. md at master · awsdocs/amazon-redshift. Redshift DateDiff is used to find the difference between the specified dates. All comparison conditions are binary operators with a Boolean return type. Find out key distinctions in architecture, performance, scaling, pricing—and more!Amazon Redshift accepts different date formats, including ISO date time strings. by the way, Just new in DBeaver. If one of the operands is a floating-point number, then Amazon Redshift promotes the other operand to a floating-point number and. Redshift is highly scalable and can handle spikes in workloads. time = b. VARBYTE type. rahulbmv. I know that I can do another query to then get the max ID but I would ideally like to just go by timestamp. Redshift クエリのパフォーマンス分析. Why is. SELECT DATEDIFF (week,'2019-01-01','2019-12-31') as numweeks; I need to analyze the time interval difference from two dates in Amazon-Redshift, for example: '2021-10-13 14:37:00' - '2021-10-13 12:00:00' = '02:37:00' or in case the days is different: Part of AWS Collective. state and a. Because it addresses very different requirements, the specialized data storage schema and query execution engine that Amazon Redshift uses are completely different. Misalnya, anggaplah bahwa Anda menghitung perbedaan dalam tahun antara dua tanggal, 12-31-2008 dan 01-01-2009. Boolean type. Also to note that: DATEDIFF. Redshift Date Time Operations. This often happens only for a few minutes. Redshift provides 2 kinds of node resizing features: Elastic resize; Classic resize; Elastic Resize. 0. The DATETIME_DIFF arguments are datetimes, not dates; Snowflake, Redshift, and Databricks’ DATEDIFF functions support multiple date types such as dates and timestamps. Use the TIMESTAMPTZ data type to input complete timestamp values that include the date, the time of day, and a time zone. Redshift joins is used to retrieve data from two or multiple tables using join conditions. This example uses the current date to find the difference between the current date and a specific date. While migrating the code from Redshift you will need to rewrite this function in Bigquery. id = table1. Find out key distinctions in architecture, performance, scaling, pricing—and more! SELECT * FROM schemaName. DIFFERENCE function. This is what i have so far. The expected result is change the date value from date to string by using to_char so that it can performs the condition = "20221220". Redshift's pricing structure is slightly more complex compared to Snowflake because there are more options specifically around node types. 1. While Amazon Redshift is performing maintenance, any queries or other operations that are in progress are shut down. DATEDIFF example The snippet can then be called in a query as shown below: select [difference_in_weekdays ('2017-06-20','2018-07-16')] Which returns 279. In MySQL, you can use TIMESTAMPDIFF function. Amazon Redshift Advisor offers recommendations about how to optimize your Amazon Redshift cluster to increase performance and save on operating costs. Share. inventory_date::date))) * 12 + EXTRACT (month FROM age ('2020-12-20'::date. You can directly convert the format by specifying the cast operator ( ‘::’) such as ::date, ::time, ::timestamp after the date string literal. 0. date_to) * 2) - CASE WHEN DATEPART(DW, evnt. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. If you're experiencing performance issues in your Amazon Redshift cluster, consider the following approaches: Monitor your cluster performance metrics. The third parameter is datepart. Categories: Date/Time. cust_id = t. Database code changes should be tracked in the same version control system as application code. Redshift first requires the user to set up collections of servers called clusters; each cluster runs an Amazon Redshift engine and holds one or more datasets. In my Redshift table I have 2 columns that stores timestamp values: start_date_time and end_date_time. DATEDIFFの結果は、 expression2 - expression1 の結果が返る。. if dlr. A data type constrains the set of values that a column or argument can contain. Follow. Elastic resize is the fasted way to resize the cluster. Your highlighted WHERE clause logic is comparing timeworkedfrom to a date six months earlier than the first of the current month. Value a is less than or equal to value b. For example, the following command doesn't return an error, even though it sets the time zone to an invalid value. Skipping weekends. Introduction to Redshift date_trunc The date_trunc function in redshift is utilized to truncate a timestamp or interval to a specified date part such as month, week, or hour. datex, Signups, Page_load FROM (SELECT CAST (mp_date AS DATE) AS datex, mp_event_name, COUNT (DISTINCT mp_device_id) AS Signups FROM mp_master_event WHERE mp_event_name = 'email_page_submit' AND datex >= DATE. Athena gave the best results, completing the scan in just 2. Note that unit values can be different in SQL Server DATEDIFF and MySQL TIMESTAMPDIFF. When an input value includes a time zone, Amazon Redshift uses the time zone to convert the value to UTC and stores the UTC value. Neste caso, a função retorna 1 ano, apesar do fato de que essas datas são apenas um dia de diferença. Redshift DateDiff; Redshift materialized views; ADVERTISEMENT. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. It is constructed with this syntax: DATEDIFF ( datepart, {date|time|timetz|timestamp}, {date|time|timetz|timestamp} ) Implementing DATEDIFF in Redshift simply computes the difference between two dates or timestamps. SUPER type. Also, 'minute'::character varying::text can simply be minute and '0. Datediff is not relevant here . This works by converting the. select to_date ( '20010631', 'YYYYMMDD', FALSE ); The result is July 1, 2001, because there are only 30 days. – Spark & PySpark SQL provides datediff() function to get the difference between two dates. trunc (created_at_date) between '2014-06-01' and '2014-06-30'; 3. CREATE TABLE ORDERS ( ID INT , PRODUCT CHAR. For example, if AUTO distribution style is specified, Amazon Redshift initially assigns the ALL distribution style to a small table. Create 1 day ranges new_start and new_end. This example uses the current date to find the difference between the current date and a specific date. To convert a date to a string use the Redshift to_char function as below. Improve this answer. Returns the count (signed integer) of the specified datepart boundaries crossed between the specified startdate and enddate. You can truncate date part such as hour, weeks, or months. select datediff (qtr, '1998-07-01', current_date); date_diff ----------- 40 (1 row) En este ejemplo, se unen las tablas SALES y LISTING para calcular cuántos días después de indicarse se vendieron los tickets de los listados 1000 a 1005. I tested this query on Redshift with the help of Workbench J. select. This question is in a collective: a subcommunity defined by tags with relevant content and experts. Redshift Date Time Operations. Create a custom policy that allows calling redshift:GetClusterCredentials and restricts the resource to a given value for DbUser. Interval literals. The DATETIME_DIFF arguments are datetimes, not dates; Snowflake, Redshift, and Databricks’ DATEDIFF functions support multiple date types such as dates and timestamps. It assumes that two given dates are business days. For this example, log on as user1 with password ez. That is go from this: 2013-12-17 12:27:50 to this: 2013-12-17 12:27:00 I have tried the following: SELECT da. how to get date difference between two dates using DateDiff Excluding the weekends. date) between -60 and 0 group by 1 ) select t1. 005479 (1 year + 2/365 years). Inner join, right outer join, left outer join, full outer join and cross join are the type of joins available in redshift. Redshift’s compression saved up to 60% of disk space which firmly establishes a dominant profile for Amazon Redshift. So, DATEDIFF (day, '2020-01-13 23:59:58', '2020-01-14 00:00:08') will return 1, even though the difference is only few seconds, because the given interval crosses the boundary of a day (midnight). ago. SELECT TIMESTAMPDIFF (SECOND, '2010-01-01 10:10:20', '2010-01-01 09:45:59') AS SECONDDIFFERENCE;I have to compare 2 separate columns to come up with the most recent date between them. Amazon Redshift treats decimal values as if they are different static types and allows all mathematical operations. 000' SELECT CAST (@EndTime - @StartTime as Time) As TimeDifference. Snowflake: DATEDIFF('day', start, stop) AS days Talha September 20th, 2021 Redshift is a completely managed data warehouse service offered by Amazon Web Services. With the argument ALL, the function retains all duplicate values from the expression for. 2 and is designed to deliver fast query and I/O performance for any size dataset. If diff is 12 hours, than result should be 0. However, we will have to exclude. Like most other SQL functions, you need to pass in arguments; for the DATE_PART function, you’ll pass in a date/timestamp/date field that you want to extract a date part from and specify the part you want removed.